数值分析课程设计。。。。。。。x=[0.25 0.3 0.39 0.45 0.53] y=[0.5000 0.5477 0.6245 0.6708 0.7280] n=length(x); for i=1:n-1 h(i)=x(i+1)-x(i); end for i=1:n-2 k(i)=h(i+1)/(h(i)+h(i+1)); u(i)=h(i)/(h(i)+h(i+1)); end for i=1:n-2 gl(i)=3*(u(i)*(y(i+2)-y(i+1))/h(i+1)+k(i
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