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[电信] 薄膜干涉的仿真程序
说明: % n1=1.2 n0=1; n2=1.5; n1=1.2; langmuda=400*10^(-9); h=0:0.0001*langmuda/1.2:langmuda/1.2; x=n1*h; j0=0; j1=asin(n0*sin(j0)/n1); f=4*pi*n1*h*cos(j1)/langmuda; a=n0-n2; b=n0+n2; c=((n0.*n2)./n1)-n1; d=((n0.*n2)./n1)+n1; A=a^2*(cos(f/2).^2)+c^2*(sin(f<qq_36242390> 上传 | 大小:53kb