说明: N=512; A=zeros(N,N); B=zeros(N,N); for I=1:1:256 J=1:1:256 ImageNum=double(Image(I,J,1)); A(I,J)=ImageNum/255; B(I,J)=0; end end figure; imshow(A); pi=3.1415926; for I=1:1:N for J=1:1:N R=rand(1,1);%生成一个元素在0,1之间均匀分布的随机矩阵R B(I,J)=A(I,J)*sin(R*2*pi);% <qq_40675570> 上传 | 大小:973byte